I already have proven that the following series converges.

In this article, I will show that:

Lemma 1. The following equations hold:


Proof. Define sn as

then a simple calculation shows that:

Dividing both sides by 2sin(x/2), the conclusion follows. By the same manner, define tn as

then we have

Dividing both sides by 2sin(x/2), the conclusion follows.

Lemma 2. The following sequence converges on any closed subntervals of (0, 2π), while α is a positive real number.

Proof. Define an(x) and bn(x) as following:

Then we have

So, ∑an is bounded. Moreover, bn decreases and converges to 0. Thus, by Dirichlet's test, ∑anbn converges uniformly.

Lemma 3. The following equation holds:

Proof. For the series converges uniformly, we have:

Thus the conclusion follows.

If we substitute x by 1, we have the desired equation:

Posted by Maria Agnesi

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  1. Convergence of the series ∑(sin(n))/n.

    Tracked from Maria Agnesi 2009/11/19 23:41 Delete

    The following series converges. To prove this fact, we first consider the identity: Substituting x by 1 and taking summation, we have or Thus ∑|sin(n)| is bounded and ∑(sin(n))/n converges by Abel-Dedekind-Dirichlet theorem. Furthermore, we can prove b...

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