Let a and b are two nonzero elements of a ring R such that ab=0. Then a and b are said to be divisors of zero (or zero divisors). In the ring Zn, the divisors of zero are precisely those nonzero elements that are not relatively prime to n. As a corollary we have that if p is a prime then Zp has no divisors of zero. Note further that the cancellation laws hold in a ring R if and only if R has no divisors of zero.
A ring in which the multipliation is commutative is called a commutative ring. A ring with a multiplicative identity element is a ring with unity; the multiplicative identity element 1 is called an unity. A multiplicative inverse of an element a in a ring R with nonzero unity 1 is an element a'∈R such that aa' = 1.
Let R be a ring with nonzero unity 1. An element u in R is a unit of R if it has a multiplicative inverse in R. If every nonzero element of R is a unit, then R is called division ring (or skew field). A field is a commutative division ring. A commutative division ring is called a strictly skew field.
By an integral domain, we mean that a commutative ring with a nonzero unity and containing no divisors of zero. We easily see that every field is an integral domain. Furthermore, we see that:
Theorem 1 Every finite integral domain is a field.
Proof. Let 0, 1, a1, a2, …, an be all the elements of a finite domain D. We need to show that for every a∈D where a≠0, there exists b∈D such that ab=1. Now consider a1, aa1, aa2, …, aan. We claim that all these elements of D are distinct, for aai=aaj implies that ai=aj by the cancellation loaws that hold inan integral domain. Also, since D has no zero divisors, none of these elements is zero. Hence by counting, we find that a1, aa1, aa2, …, aan are elements 1, a1, a2, …, an in some order, so that either a1=1, that is a-1, or aai=1 for some i. Thus a has a multiplicative inverse. QED.
Corollary 2 If p is a prime, then Zp is a field.
Remark: Corollary 2 can be derived from Fermat's Little Theorem. (See 70th article.)
In fact the antecedent of Theorem 1 can be weaken as follows:
Theorem 3 (Wedderburn) Every finite division ring is a field.
The proof of Theorem 3 is too long to write in HTML, so I attach a PDF file of the proof:
References:
Homepage of DEPT of Mathematics in Colgate University
John B. Fraleigh, A First Course in Abstract Algebra 7ed, Addison-Wesley
Posted by Maria Agnesi
Agnesi_090304_a_finite_division_ring_is_a_field.pdf